Wednesday, May 29, 2019

Raising and lowering operators.

These videos show how raising and lowering operators are defined and used for the one-dimensional harmonic oscillator (1DHO). It uses the same notation as Griffiths, chapter 2.
The two key equations you need in order to use the operators are:
\(a_- | n \rangle = \sqrt{n}\: |n-1 \rangle \),
\(a_+ | n \rangle = \sqrt{n+1} \: |n+1 \rangle \).

This is shown at about 24:25 of the third video (using a- a+). Everything before that is derivation.






11 comments:

  1. I think the residues are sqrt(n) for a- and sqrt(n+1) for a+. Easy thing to forget, I did the same thing on my first try.

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    Replies
    1. Agree! Is there a specific mistake in a video on that?

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    2. I see what you mean now. In the last video there is a mistake.

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    3. Hopefully everyone can find that. In the evaluation of the 2|2 term.

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    4. Oh, so we multiply by the square root of n or (n+1), not just multiply by n or (n+1) like its done in the third video?

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    5. The two key equations you need in order to use the operators are:

      \(a_- | n \rangle = \sqrt{n}\: |n-1 \rangle \),

      \(a_+ | n \rangle = \sqrt{n+1} \: |n+1 \rangle \).

      This is shown at about 24:25 of the third video (using a- a+). Everything before that is derivation.

      Delete
    6. Hi Nick. I am not sure exactly where you mean in the third video. The part at 24:25 is correct and uses The two key equations you need in order to use the operators are:

      \(a_- | n \rangle = \sqrt{n}\: |n-1 \rangle \),

      \(a_+ | n \rangle = \sqrt{n+1} \: |n+1 \rangle \).

      Delete
    7. so, yes, you do want the square root.

      Delete
  2. In the second video the part where the lowering operator is operating on /psi_{n} is it supposed to be equal to c_{n}* | /psi_{n+1} > or c_{n+1}* | /psi_{n+1} >

    ReplyDelete
    Replies
    1. I ask because in the previous line it is c_{n+1}* | /psi_{n+1} >

      Delete
    2. The two key equations you need in order to use the operators are:

      \(a_- | n \rangle = \sqrt{n}\: |n-1 \rangle \),

      \(a_+ | n \rangle = \sqrt{n+1} \: |n+1 \rangle \).

      This is shown at about 24:25 of the third video (using a- a+). Everything before that is derivation.

      Delete

Midterm 2 solutions

Here are solutions to midterm 2. I see that I did not write it in the solutions, but it is helpful for sp2 type integrals to recall that \(\...